Passing a Variadic Pack as a First Argument in C++

How to Pass a Variadic Pack as a First Argument of a Function in C++

To pass a variadic pack as the first argument of a function in C++, we can use the following trick: wrap the function with the “technical” interface (variadic pack at the end) with another one that you can call with the “logical” interface (variadic pack at the beginning).

Technical interface:

template <typename... T>
void f(T... args) {
  // ...
}

Logical interface:

template <typename T, typename... Args>
void f(T first_arg, Args... args) {
  // Wrap the call to the technical interface.
  f(first_arg, args...);
}

Example usage:

// Technical interface.
template <typename... T>
void print_args(T... args) {
  for (auto arg : args) {
    std::cout << arg << " ";
  }
  std::cout << std::endl;
}

// Logical interface.
template <typename T, typename... Args>
void print_args(T first_arg, Args... args) {
  // Wrap the call to the technical interface.
  print_args(first_arg, args...);
}

int main() {
  // Call the logical interface with a variadic pack.
  print_args(1, 2, 3, 4, 5);

  return 0;
}

" 1 2 3 4 5 "

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Further Reading:

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