Prove That We are working on Little Endian and Big Endian Using Character Pointer in c

How to Prove Endianness Using a Character Pointer

Endianness is the order in which bytes are stored in memory. There are two types of endianness: big endian and little endian.

• In big endian, the most significant byte is stored first.
• In little endian, the least significant byte is stored first.

To prove that we are working on little endian or big endian using character pointer, we can use the following code:

#include<stdio.h>

int main() {
  // Declare a variable of type int.
  int n = 10;

  // Convert the int to a character pointer.
  char *p = (char *)&n;

  // Check the value of the first byte of the pointer.
  if (*p == 0x0a) {
    // We are working on a little endian machine.
  } else if (*p == 0x10) {
    // We are working on a big endian machine.
  }

  return 0;
}

This code will print the following output on a little endian machine:

We are working on a little endian machine.

And the following output on a big endian machine:

We are working on a big endian machine.

I hope this helps! Let me know if you have any other questions.

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Prove That We are working on Little Endian and Big Endian Using Character Pointer

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