Write a program to 50 % reversing of given number in c
C Program: Reverse 50% of Given Number
"50% reversing of a given number" means reversing only the first half of the digits in the given number. For example, if the input number is 123456, the first half (123) would be reversed to get 321456. If the input number has an odd number of digits, the first half is rounded down. For example, if the input number is 12345, the first half (12) would be reversed to get 32145.
#include<stdio.h>
int main()
{
int a[10],i,j,t,ele;
ele=sizeof(a)/sizeof(a[0]);
printf("Enter array:");
for(i=0;i<ele;i++)
scanf("%d",&a[i]);
printf("Before:");
for(i=0;i<ele;i++)
printf(" %d",a[i]);
printf("\n");
// for(i=0,j=5;j<ele;i++,j++)
for(i=0,j=5;i<ele/2;i++,j++)
{
t=a[i];
a[i]=a[j];
a[j]=t;
}
printf("After:");
for(i=0;i<ele;i++)
printf(" %d",a[i]);
printf("\n");
}Output:
Enter array: 60 70 80 90 100 10 20 30 40 50
Before: 60 70 80 90 100 10 20 30 40 50
After: 10 20 30 40 50 60 70 80 90 100
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Further Reading:
Note: If you encounter any issues or specific errors when running this program, please let me know and I'll be happy to help debug them!