Design a function to check the given number is Armstrong or not if Armstrong return 1 else 0

Design a C Function to Check if a Number is Armstrong or Not

"Design a function to check the given number is Armstrong or not if Armstrong return 1 else 0" means that you are asked to write a function that takes a number as an argument and checks whether it is an Armstrong number or not. If the number is an Armstrong number, the function should return 1 (which indicates true). Otherwise, the function should return 0 (which indicates false).

An Armstrong number is a number where the sum of each digit raised to the power of the number of digits in the number is equal to the original number. For example, 153 is an Armstrong number because 1^3 + 5^3 + 3^3 = 153.

So, the function should check whether the input number meets this condition and return 1 if it is an Armstrong number or 0 if it is not.

To design a function to check if a given number is Armstrong in C, we can use the following steps:

Declare the function prototype. This tells the compiler the name of the function, its return type, and the type of its arguments.

int isArmstrong(int n);

Implement the function body. This is where the code to check if the number is Armstrong goes.

int isArmstrong(int n) {
  // Calculate the number of digits in the number.
  int digits = 0;
  while (n > 0) {
    digits++;
    n /= 10;
  }

  // Calculate the sum of the cubes of the digits.
  int sum = 0;
  for (int i = 0; i < digits; i++) {
    int digit = n % 10;
    sum += digit * digit * digit;
    n /= 10;
  }

  // Return 1 if the sum is equal to the number, else return 0.
  return sum == n;
}

Use the function in your main program.

int main() {
  int n;
  printf("Enter a number: ");
  scanf("%d", &n);

  if (isArmstrong(n)) {
    printf("%d is an Armstrong number.\n", n);
  } else {
    printf("%d is not an Armstrong number.\n", n);
  }

  return 0;
}

Enter a number: 153
153 is an Armstrong number.