Design a function to swapping of two number
Design a Function for Swapping Two Numbers in C
"Design a function to swapping of two numbers" means that you are asked to write a function that takes two numbers as input and swaps their values. In other words, the function should exchange the values of the two input numbers so that the first number becomes the second number, and the second number becomes the first number.
Swapping of two number in C, we can use the following algorithm:
- Create a temporary variable to store the value of the first number.
- Assign the value of the second number to the first number.
- Assign the value of the temporary variable to the second number.
This algorithm can be implemented in C as follows:
void swap(int *a, int *b) {
int temp = *a;
*a = *b;
*b = temp;
}The swap() function takes two pointers to integers as input and swaps the values of the integers that the pointers point to.
To use the swap() function, we can simply pass in the addresses of the two numbers that we want to swap. For example, the following code swaps the values of the variables x and y:
int x = 10;
int y = 20;
swap(&x, &y);
printf("x = %d, y = %d\n", x, y);Output:
x = 20, y = 10We can also use the swap() function to swap the values of two elements in an array. For example, the following code swaps the values of the first two elements in the array arr:
int arr[5] = {1, 2, 3, 4, 5};
swap(&arr[0], &arr[1]);
printf("arr[0] = %d, arr[1] = %d\n", arr[0], arr[1]);Output:
arr[0] = 2, arr[1] = 1write c program to Swapping of two number
#include<stdio.h>
void swap(int *,int *);
void main()
{
int num1,num2;
printf("Enetr two numnber:");
scanf("%d %d",&num1,&num2);
printf("Before swapping :%d %d\n",num1,num2);
swap(&num1,&num2);
printf("After swapping: %d %d\n",num1,num2);
}
void swap(int *n1,int *n2)
{
int temp;
temp=*n1;
*n1=*n2;
*n2=temp;
}
output:
Enter two numbers: 10 20
Before swapping:10 20
After swapping: 20 10Further Reading:
Concatenating Two Strings in C: A Step-by-Step Guide
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